5(2x-1)+2(2x-1)=3(3x-4)-(2-3x)

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Solution for 5(2x-1)+2(2x-1)=3(3x-4)-(2-3x) equation: 



5(2x-1)+2(2x-1)=3(3x-4)-(2-3x)

We move all terms to the left:

5(2x-1)+2(2x-1)-(3(3x-4)-(2-3x))=0

We add all the numbers together, and all the variables

5(2x-1)+2(2x-1)-(3(3x-4)-(-3x+2))=0

We multiply parentheses

10x+4x-(3(3x-4)-(-3x+2))-5-2=0



We calculate terms in parentheses: -(3(3x-4)-(-3x+2)), so:

3(3x-4)-(-3x+2)

We multiply parentheses

9x-(-3x+2)-12

We get rid of parentheses

9x+3x-2-12

We add all the numbers together, and all the variables

12x-14

Back to the equation:

-(12x-14)



We add all the numbers together, and all the variables

14x-(12x-14)-7=0

We get rid of parentheses

14x-12x+14-7=0

We add all the numbers together, and all the variables

2x+7=0

We move all terms containing x to the left, all other terms to the right

2x=-7

x=-7/2

x=-3+1/2

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