5(2x+3)=8(x-1)+7

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Solution for 5(2x+3)=8(x-1)+7 equation:



5(2x+3)=8(x-1)+7
We move all terms to the left:
5(2x+3)-(8(x-1)+7)=0
We multiply parentheses
10x-(8(x-1)+7)+15=0
We calculate terms in parentheses: -(8(x-1)+7), so:
8(x-1)+7
We multiply parentheses
8x-8+7
We add all the numbers together, and all the variables
8x-1
Back to the equation:
-(8x-1)
We get rid of parentheses
10x-8x+1+15=0
We add all the numbers together, and all the variables
2x+16=0
We move all terms containing x to the left, all other terms to the right
2x=-16
x=-16/2
x=-8

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