5(2x+3)=4(x+1)+2

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Solution for 5(2x+3)=4(x+1)+2 equation: 



5(2x+3)=4(x+1)+2

We move all terms to the left:

5(2x+3)-(4(x+1)+2)=0

We multiply parentheses

10x-(4(x+1)+2)+15=0



We calculate terms in parentheses: -(4(x+1)+2), so:

4(x+1)+2

We multiply parentheses

4x+4+2

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We get rid of parentheses

10x-4x-6+15=0

We add all the numbers together, and all the variables

6x+9=0

We move all terms containing x to the left, all other terms to the right

6x=-9

x=-9/6

x=-1+1/2

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