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5(2x+3)=37-2(5x-1)
We move all terms to the left:
5(2x+3)-(37-2(5x-1))=0
We multiply parentheses
10x-(37-2(5x-1))+15=0
We calculate terms in parentheses: -(37-2(5x-1)), so:We get rid of parentheses
37-2(5x-1)
determiningTheFunctionDomain -2(5x-1)+37
We multiply parentheses
-10x+2+37
We add all the numbers together, and all the variables
-10x+39
Back to the equation:
-(-10x+39)
10x+10x-39+15=0
We add all the numbers together, and all the variables
20x-24=0
We move all terms containing x to the left, all other terms to the right
20x=24
x=24/20
x=1+1/5
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