5(2x+3)=3(x+2)+7+9

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Solution for 5(2x+3)=3(x+2)+7+9 equation: 



5(2x+3)=3(x+2)+7+9

We move all terms to the left:

5(2x+3)-(3(x+2)+7+9)=0

We multiply parentheses

10x-(3(x+2)+7+9)+15=0



We calculate terms in parentheses: -(3(x+2)+7+9), so:

3(x+2)+7+9

We add all the numbers together, and all the variables

3(x+2)+16

We multiply parentheses

3x+6+16

We add all the numbers together, and all the variables

3x+22

Back to the equation:

-(3x+22)



We get rid of parentheses

10x-3x-22+15=0

We add all the numbers together, and all the variables

7x-7=0

We move all terms containing x to the left, all other terms to the right

7x=7

x=7/7

x=1

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