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5(2x+3)=2(5+5x)
We move all terms to the left:
5(2x+3)-(2(5+5x))=0
We add all the numbers together, and all the variables
5(2x+3)-(2(5x+5))=0
We multiply parentheses
10x-(2(5x+5))+15=0
We calculate terms in parentheses: -(2(5x+5)), so:We get rid of parentheses
2(5x+5)
We multiply parentheses
10x+10
Back to the equation:
-(10x+10)
10x-10x-10+15=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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