5(2x+3)=11(9-x)

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Solution for 5(2x+3)=11(9-x) equation: 



5(2x+3)=11(9-x)

We move all terms to the left:

5(2x+3)-(11(9-x))=0

We add all the numbers together, and all the variables

5(2x+3)-(11(-1x+9))=0

We multiply parentheses

10x-(11(-1x+9))+15=0



We calculate terms in parentheses: -(11(-1x+9)), so:

11(-1x+9)

We multiply parentheses

-11x+99

Back to the equation:

-(-11x+99)



We get rid of parentheses

10x+11x-99+15=0

We add all the numbers together, and all the variables

21x-84=0

We move all terms containing x to the left, all other terms to the right

21x=84

x=84/21

x=4

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