5(2x+3)=-3x+28

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Solution for 5(2x+3)=-3x+28 equation: 



5(2x+3)=-3x+28

We move all terms to the left:

5(2x+3)-(-3x+28)=0

We multiply parentheses

10x-(-3x+28)+15=0

We get rid of parentheses

10x+3x-28+15=0

We add all the numbers together, and all the variables

13x-13=0

We move all terms containing x to the left, all other terms to the right

13x=13

x=13/13

x=1

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