5(2x+3)-7=2(x+2)

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Solution for 5(2x+3)-7=2(x+2) equation: 



5(2x+3)-7=2(x+2)

We move all terms to the left:

5(2x+3)-7-(2(x+2))=0

We multiply parentheses

10x-(2(x+2))+15-7=0



We calculate terms in parentheses: -(2(x+2)), so:

2(x+2)

We multiply parentheses

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

10x-(2x+4)+8=0

We get rid of parentheses

10x-2x-4+8=0

We add all the numbers together, and all the variables

8x+4=0

We move all terms containing x to the left, all other terms to the right

8x=-4

x=-4/8

x=-1/2

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