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5(2x+3)-4=4(2x+1)+1
We move all terms to the left:
5(2x+3)-4-(4(2x+1)+1)=0
We multiply parentheses
10x-(4(2x+1)+1)+15-4=0
We calculate terms in parentheses: -(4(2x+1)+1), so:We add all the numbers together, and all the variables
4(2x+1)+1
We multiply parentheses
8x+4+1
We add all the numbers together, and all the variables
8x+5
Back to the equation:
-(8x+5)
10x-(8x+5)+11=0
We get rid of parentheses
10x-8x-5+11=0
We add all the numbers together, and all the variables
2x+6=0
We move all terms containing x to the left, all other terms to the right
2x=-6
x=-6/2
x=-3
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