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5(2x+3)-4=2(3-2x+1)
We move all terms to the left:
5(2x+3)-4-(2(3-2x+1))=0
We add all the numbers together, and all the variables
5(2x+3)-(2(-2x+4))-4=0
We multiply parentheses
10x-(2(-2x+4))+15-4=0
We calculate terms in parentheses: -(2(-2x+4)), so:We add all the numbers together, and all the variables
2(-2x+4)
We multiply parentheses
-4x+8
Back to the equation:
-(-4x+8)
10x-(-4x+8)+11=0
We get rid of parentheses
10x+4x-8+11=0
We add all the numbers together, and all the variables
14x+3=0
We move all terms containing x to the left, all other terms to the right
14x=-3
x=-3/14
x=-3/14
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