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5(2x+3)-3(x+3)=20
We move all terms to the left:
5(2x+3)-3(x+3)-(20)=0
We multiply parentheses
10x-3x+15-9-20=0
We add all the numbers together, and all the variables
7x-14=0
We move all terms containing x to the left, all other terms to the right
7x=14
x=14/7
x=2
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