5(2x+3)+6(x-2)=11

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Solution for 5(2x+3)+6(x-2)=11 equation: 



5(2x+3)+6(x-2)=11

We move all terms to the left:

5(2x+3)+6(x-2)-(11)=0

We multiply parentheses

10x+6x+15-12-11=0

We add all the numbers together, and all the variables

16x-8=0

We move all terms containing x to the left, all other terms to the right

16x=8

x=8/16

x=1/2

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