5(2x+2)=2(x-1)+2x-4=48

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Solution for 5(2x+2)=2(x-1)+2x-4=48 equation: 



5(2x+2)=2(x-1)+2x-4=48

We move all terms to the left:

5(2x+2)-(2(x-1)+2x-4)=0

We multiply parentheses

10x-(2(x-1)+2x-4)+10=0



We calculate terms in parentheses: -(2(x-1)+2x-4), so:

2(x-1)+2x-4

We add all the numbers together, and all the variables

2x+2(x-1)-4

We multiply parentheses

2x+2x-2-4

We add all the numbers together, and all the variables

4x-6

Back to the equation:

-(4x-6)



We get rid of parentheses

10x-4x+6+10=0

We add all the numbers together, and all the variables

6x+16=0

We move all terms containing x to the left, all other terms to the right

6x=-16

x=-16/6

x=-2+2/3

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