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5(2x+1)=9(x+5)+5
We move all terms to the left:
5(2x+1)-(9(x+5)+5)=0
We multiply parentheses
10x-(9(x+5)+5)+5=0
We calculate terms in parentheses: -(9(x+5)+5), so:We get rid of parentheses
9(x+5)+5
We multiply parentheses
9x+45+5
We add all the numbers together, and all the variables
9x+50
Back to the equation:
-(9x+50)
10x-9x-50+5=0
We add all the numbers together, and all the variables
x-45=0
We move all terms containing x to the left, all other terms to the right
x=45
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