5(2x+1)=8(x-2)

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Solution for 5(2x+1)=8(x-2) equation: 



5(2x+1)=8(x-2)

We move all terms to the left:

5(2x+1)-(8(x-2))=0

We multiply parentheses

10x-(8(x-2))+5=0



We calculate terms in parentheses: -(8(x-2)), so:

8(x-2)

We multiply parentheses

8x-16

Back to the equation:

-(8x-16)



We get rid of parentheses

10x-8x+16+5=0

We add all the numbers together, and all the variables

2x+21=0

We move all terms containing x to the left, all other terms to the right

2x=-21

x=-21/2

x=-10+1/2

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