5(2x+1)=6(x-2)+37

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Solution for 5(2x+1)=6(x-2)+37 equation: 



5(2x+1)=6(x-2)+37

We move all terms to the left:

5(2x+1)-(6(x-2)+37)=0

We multiply parentheses

10x-(6(x-2)+37)+5=0



We calculate terms in parentheses: -(6(x-2)+37), so:

6(x-2)+37

We multiply parentheses

6x-12+37

We add all the numbers together, and all the variables

6x+25

Back to the equation:

-(6x+25)



We get rid of parentheses

10x-6x-25+5=0

We add all the numbers together, and all the variables

4x-20=0

We move all terms containing x to the left, all other terms to the right

4x=20

x=20/4

x=5

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