5(2x+1)=6(3x+1)-7

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Solution for 5(2x+1)=6(3x+1)-7 equation: 



5(2x+1)=6(3x+1)-7

We move all terms to the left:

5(2x+1)-(6(3x+1)-7)=0

We multiply parentheses

10x-(6(3x+1)-7)+5=0



We calculate terms in parentheses: -(6(3x+1)-7), so:

6(3x+1)-7

We multiply parentheses

18x+6-7

We add all the numbers together, and all the variables

18x-1

Back to the equation:

-(18x-1)



We get rid of parentheses

10x-18x+1+5=0

We add all the numbers together, and all the variables

-8x+6=0

We move all terms containing x to the left, all other terms to the right

-8x=-6

x=-6/-8

x=3/4

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