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5(2x+1)=5x+2(1+x)+9
We move all terms to the left:
5(2x+1)-(5x+2(1+x)+9)=0
We add all the numbers together, and all the variables
5(2x+1)-(5x+2(x+1)+9)=0
We multiply parentheses
10x-(5x+2(x+1)+9)+5=0
We calculate terms in parentheses: -(5x+2(x+1)+9), so:We get rid of parentheses
5x+2(x+1)+9
We multiply parentheses
5x+2x+2+9
We add all the numbers together, and all the variables
7x+11
Back to the equation:
-(7x+11)
10x-7x-11+5=0
We add all the numbers together, and all the variables
3x-6=0
We move all terms containing x to the left, all other terms to the right
3x=6
x=6/3
x=2
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