5(2x+1)=3(x-4)5

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Solution for 5(2x+1)=3(x-4)5 equation: 



5(2x+1)=3(x-4)5

We move all terms to the left:

5(2x+1)-(3(x-4)5)=0

We multiply parentheses

10x-(3(x-4)5)+5=0



We calculate terms in parentheses: -(3(x-4)5), so:

3(x-4)5

We multiply parentheses

15x-60

Back to the equation:

-(15x-60)



We get rid of parentheses

10x-15x+60+5=0

We add all the numbers together, and all the variables

-5x+65=0

We move all terms containing x to the left, all other terms to the right

-5x=-65

x=-65/-5

x=+13

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