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5(2x+1)=3(x+4)=-5
We move all terms to the left:
5(2x+1)-(3(x+4))=0
We multiply parentheses
10x-(3(x+4))+5=0
We calculate terms in parentheses: -(3(x+4)), so:We get rid of parentheses
3(x+4)
We multiply parentheses
3x+12
Back to the equation:
-(3x+12)
10x-3x-12+5=0
We add all the numbers together, and all the variables
7x-7=0
We move all terms containing x to the left, all other terms to the right
7x=7
x=7/7
x=1
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