5(2x+1)=3(x+4)-55(2x+1)=3(x+4)

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Solution for 5(2x+1)=3(x+4)-55(2x+1)=3(x+4) equation: 



5(2x+1)=3(x+4)-55(2x+1)=3(x+4)

We move all terms to the left:

5(2x+1)-(3(x+4)-55(2x+1))=0

We multiply parentheses

10x-(3(x+4)-55(2x+1))+5=0



We calculate terms in parentheses: -(3(x+4)-55(2x+1)), so:

3(x+4)-55(2x+1)

We multiply parentheses

3x-110x+12-55

We add all the numbers together, and all the variables

-107x-43

Back to the equation:

-(-107x-43)



We get rid of parentheses

10x+107x+43+5=0

We add all the numbers together, and all the variables

117x+48=0

We move all terms containing x to the left, all other terms to the right

117x=-48

x=-48/117

x=-16/39

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