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5(2x+1)=3(3x+7)
We move all terms to the left:
5(2x+1)-(3(3x+7))=0
We multiply parentheses
10x-(3(3x+7))+5=0
We calculate terms in parentheses: -(3(3x+7)), so:We get rid of parentheses
3(3x+7)
We multiply parentheses
9x+21
Back to the equation:
-(9x+21)
10x-9x-21+5=0
We add all the numbers together, and all the variables
x-16=0
We move all terms containing x to the left, all other terms to the right
x=16
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