5(2x+1)/7-x-2/2=6/14+4/14-3/7-2(x-1)/2

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Solution for 5(2x+1)/7-x-2/2=6/14+4/14-3/7-2(x-1)/2 equation:


x in (-oo:+oo)

(5*(2*x+1))/7-x-(2/2) = 6/14-((2*(x-1))/2)+4/14-(3/7) // - 6/14-((2*(x-1))/2)+4/14-(3/7)

(5*(2*x+1))/7+(2*(x-1))/2-x-(2/2)-(6/14)-(4/14)+3/7 = 0

(5*(2*x+1))/7+(2*(x-1))/2-x-3/7-2/7+3/7-1 = 0

(5*(2*x+1))/7+x-x-3/7-2/7+3/7-1-1 = 0

(5*(2*x+1))/7+(7*(x-1))/7+(7*(-x))/7-3/7-2/7+3/7+(-1*7)/7 = 0

5*(2*x+1)+7*(x-1)+7*(-x)-1*7-3-2+3 = 0

17*x-7*x-7-3-2-2+3 = 0

10*x-7-3-2-2+3 = 0

10*x-7-5-2+3 = 0

10*x-7-7+3 = 0

10*x-7-4 = 0

10*x-11 = 0

(10*x-11)/7 = 0

(10*x-11)/7 = 0 // * 7

10*x-11 = 0

10*x-11 = 0 // + 11

10*x = 11 // : 10

x = 11/10

x = 11/10

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