5(2x+1)+4=6(3x+2)-7

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Solution for 5(2x+1)+4=6(3x+2)-7 equation: 



5(2x+1)+4=6(3x+2)-7

We move all terms to the left:

5(2x+1)+4-(6(3x+2)-7)=0

We multiply parentheses

10x-(6(3x+2)-7)+5+4=0



We calculate terms in parentheses: -(6(3x+2)-7), so:

6(3x+2)-7

We multiply parentheses

18x+12-7

We add all the numbers together, and all the variables

18x+5

Back to the equation:

-(18x+5)



We add all the numbers together, and all the variables

10x-(18x+5)+9=0

We get rid of parentheses

10x-18x-5+9=0

We add all the numbers together, and all the variables

-8x+4=0

We move all terms containing x to the left, all other terms to the right

-8x=-4

x=-4/-8

x=1/2

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