5(2v-12)+v=5(v+12)

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Solution for 5(2v-12)+v=5(v+12) equation: 



5(2v-12)+v=5(v+12)

We move all terms to the left:

5(2v-12)+v-(5(v+12))=0

We add all the numbers together, and all the variables

v+5(2v-12)-(5(v+12))=0

We multiply parentheses

v+10v-(5(v+12))-60=0



We calculate terms in parentheses: -(5(v+12)), so:

5(v+12)

We multiply parentheses

5v+60

Back to the equation:

-(5v+60)



We add all the numbers together, and all the variables

11v-(5v+60)-60=0

We get rid of parentheses

11v-5v-60-60=0

We add all the numbers together, and all the variables

6v-120=0

We move all terms containing v to the left, all other terms to the right

6v=120

v=120/6

v=20

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