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5(2v+3)-2=12v+12-2v
We move all terms to the left:
5(2v+3)-2-(12v+12-2v)=0
We add all the numbers together, and all the variables
5(2v+3)-(10v+12)-2=0
We multiply parentheses
10v-(10v+12)+15-2=0
We get rid of parentheses
10v-10v-12+15-2=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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