5(2t-2)+12=4(t-3)-(2t+3)

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Solution for 5(2t-2)+12=4(t-3)-(2t+3) equation: 



5(2t-2)+12=4(t-3)-(2t+3)

We move all terms to the left:

5(2t-2)+12-(4(t-3)-(2t+3))=0

We multiply parentheses

10t-(4(t-3)-(2t+3))-10+12=0



We calculate terms in parentheses: -(4(t-3)-(2t+3)), so:

4(t-3)-(2t+3)

We multiply parentheses

4t-(2t+3)-12

We get rid of parentheses

4t-2t-3-12

We add all the numbers together, and all the variables

2t-15

Back to the equation:

-(2t-15)



We add all the numbers together, and all the variables

10t-(2t-15)+2=0

We get rid of parentheses

10t-2t+15+2=0

We add all the numbers together, and all the variables

8t+17=0

We move all terms containing t to the left, all other terms to the right

8t=-17

t=-17/8

t=-2+1/8

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