5(2s+3)=27

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Solution for 5(2s+3)=27 equation: 



5(2s+3)=27

We move all terms to the left:

5(2s+3)-(27)=0

We multiply parentheses

10s+15-27=0

We add all the numbers together, and all the variables

10s-12=0

We move all terms containing s to the left, all other terms to the right

10s=12

s=12/10

s=1+1/5

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