5(2r-2)/7=(5r-2)/5

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Solution for 5(2r-2)/7=(5r-2)/5 equation: 


r in (-oo:+oo)

(5*(2*r-2))/7 = (5*r-2)/5 // - (5*r-2)/5

(5*(2*r-2))/7-((5*r-2)/5) = 0

(5*(2*r-2))/7+(-1*(5*r-2))/5 = 0

(5^2*(2*r-2))/(5*7)+(-1*7*(5*r-2))/(5*7) = 0

5^2*(2*r-2)-1*7*(5*r-2) = 0

15*r-36 = 0

(15*r-36)/(5*7) = 0

(15*r-36)/(5*7) = 0 // * 5*7

15*r-36 = 0

15*r-36 = 0 // + 36

15*r = 36 // : 15

r = 36/15

r = 12/5

r = 12/5

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