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5(2r+4)=3(2r+9)+4r+-7
We move all terms to the left:
5(2r+4)-(3(2r+9)+4r+-7)=0
We use the square of the difference formula
5(2r+4)-(3(2r+9)+4r-7)=0
We multiply parentheses
10r-(3(2r+9)+4r-7)+20=0
We calculate terms in parentheses: -(3(2r+9)+4r-7), so:We get rid of parentheses
3(2r+9)+4r-7
We add all the numbers together, and all the variables
4r+3(2r+9)-7
We multiply parentheses
4r+6r+27-7
We add all the numbers together, and all the variables
10r+20
Back to the equation:
-(10r+20)
10r-10r-20+20=0
We add all the numbers together, and all the variables
=0
r=0/1
r=0
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