5(2r+3)=10(r+7)-5

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Solution for 5(2r+3)=10(r+7)-5 equation:


Simplifying
5(2r + 3) = 10(r + 7) + -5

Reorder the terms:
5(3 + 2r) = 10(r + 7) + -5
(3 * 5 + 2r * 5) = 10(r + 7) + -5
(15 + 10r) = 10(r + 7) + -5

Reorder the terms:
15 + 10r = 10(7 + r) + -5
15 + 10r = (7 * 10 + r * 10) + -5
15 + 10r = (70 + 10r) + -5

Reorder the terms:
15 + 10r = 70 + -5 + 10r

Combine like terms: 70 + -5 = 65
15 + 10r = 65 + 10r

Add '-10r' to each side of the equation.
15 + 10r + -10r = 65 + 10r + -10r

Combine like terms: 10r + -10r = 0
15 + 0 = 65 + 10r + -10r
15 = 65 + 10r + -10r

Combine like terms: 10r + -10r = 0
15 = 65 + 0
15 = 65

Solving
15 = 65

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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