5(2n-8)+4n=-20+2(-10-2n)

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Solution for 5(2n-8)+4n=-20+2(-10-2n) equation: 



5(2n-8)+4n=-20+2(-10-2n)

We move all terms to the left:

5(2n-8)+4n-(-20+2(-10-2n))=0

We add all the numbers together, and all the variables

5(2n-8)+4n-(-20+2(-2n-10))=0

We add all the numbers together, and all the variables

4n+5(2n-8)-(-20+2(-2n-10))=0

We multiply parentheses

4n+10n-(-20+2(-2n-10))-40=0



We calculate terms in parentheses: -(-20+2(-2n-10)), so:

-20+2(-2n-10)

determiningTheFunctionDomain
2(-2n-10)-20

We multiply parentheses

-4n-20-20

We add all the numbers together, and all the variables

-4n-40

Back to the equation:

-(-4n-40)



We add all the numbers together, and all the variables

14n-(-4n-40)-40=0

We get rid of parentheses

14n+4n+40-40=0

We add all the numbers together, and all the variables

18n=0

n=0/18

n=0

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