5(2n-1)+8=2n-1+4(2n+1)

Solution for 5(2n-1)+8=2n-1+4(2n+1) equation:

5(2n-1)+8=2n-1+4(2n+1)

We move all terms to the left:

5(2n-1)+8-(2n-1+4(2n+1))=0

We multiply parentheses

10n-(2n-1+4(2n+1))-5+8=0


We calculate terms in parentheses: -(2n-1+4(2n+1)), so:

2n-1+4(2n+1)

determiningTheFunctionDomain
2n+4(2n+1)-1

We multiply parentheses

2n+8n+4-1

We add all the numbers together, and all the variables

10n+3

Back to the equation:

-(10n+3)


We add all the numbers together, and all the variables

10n-(10n+3)+3=0

We get rid of parentheses

10n-10n-3+3=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0