5(2n+10)=10-10(-2n-2)

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Solution for 5(2n+10)=10-10(-2n-2) equation: 



5(2n+10)=10-10(-2n-2)

We move all terms to the left:

5(2n+10)-(10-10(-2n-2))=0

We multiply parentheses

10n-(10-10(-2n-2))+50=0



We calculate terms in parentheses: -(10-10(-2n-2)), so:

10-10(-2n-2)

determiningTheFunctionDomain
-10(-2n-2)+10

We multiply parentheses

20n+20+10

We add all the numbers together, and all the variables

20n+30

Back to the equation:

-(20n+30)



We get rid of parentheses

10n-20n-30+50=0

We add all the numbers together, and all the variables

-10n+20=0

We move all terms containing n to the left, all other terms to the right

-10n=-20

n=-20/-10

n=+2

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