5(2k-4)=12-24-2(k+2)

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Solution for 5(2k-4)=12-24-2(k+2) equation:



5(2k-4)=12-24-2(k+2)
We move all terms to the left:
5(2k-4)-(12-24-2(k+2))=0
We multiply parentheses
10k-(12-24-2(k+2))-20=0
We calculate terms in parentheses: -(12-24-2(k+2)), so:
12-24-2(k+2)
determiningTheFunctionDomain -2(k+2)+12-24
We add all the numbers together, and all the variables
-2(k+2)-12
We multiply parentheses
-2k-4-12
We add all the numbers together, and all the variables
-2k-16
Back to the equation:
-(-2k-16)
We get rid of parentheses
10k+2k+16-20=0
We add all the numbers together, and all the variables
12k-4=0
We move all terms containing k to the left, all other terms to the right
12k=4
k=4/12
k=1/3

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