5(2k-3)-3(k+4)/3k+2

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Solution for 5(2k-3)-3(k+4)/3k+2 equation: 


k in (-oo:+oo)

5*(2*k-3)-(k*((3*(k+4))/3))+2 = 0

5*(2*k-3)-(k*(k+4))+2 = 0

5*(2*k-3)-1*k*(k+4)+2 = 0

5*(2*k-3)-1*k*(k+4)+2 = 0

6*k-k^2-15+2 = 0

6*k-k^2-13 = 0

6*k-k^2-13 = 0

6*k-k^2-13 = 0

DELTA = 6^2-(-13*(-1)*4)

DELTA = -16

DELTA < 0

1 = 0

1 = 0

k belongs to the empty set

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