5(2k-1)+3=6k+4(7k-5)

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Solution for 5(2k-1)+3=6k+4(7k-5) equation: 



5(2k-1)+3=6k+4(7k-5)

We move all terms to the left:

5(2k-1)+3-(6k+4(7k-5))=0

We multiply parentheses

10k-(6k+4(7k-5))-5+3=0



We calculate terms in parentheses: -(6k+4(7k-5)), so:

6k+4(7k-5)

We multiply parentheses

6k+28k-20

We add all the numbers together, and all the variables

34k-20

Back to the equation:

-(34k-20)



We add all the numbers together, and all the variables

10k-(34k-20)-2=0

We get rid of parentheses

10k-34k+20-2=0

We add all the numbers together, and all the variables

-24k+18=0

We move all terms containing k to the left, all other terms to the right

-24k=-18

k=-18/-24

k=3/4

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