5(2f-4)=7(f+3)+1

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Solution for 5(2f-4)=7(f+3)+1 equation:


Simplifying
5(2f + -4) = 7(f + 3) + 1

Reorder the terms:
5(-4 + 2f) = 7(f + 3) + 1
(-4 * 5 + 2f * 5) = 7(f + 3) + 1
(-20 + 10f) = 7(f + 3) + 1

Reorder the terms:
-20 + 10f = 7(3 + f) + 1
-20 + 10f = (3 * 7 + f * 7) + 1
-20 + 10f = (21 + 7f) + 1

Reorder the terms:
-20 + 10f = 21 + 1 + 7f

Combine like terms: 21 + 1 = 22
-20 + 10f = 22 + 7f

Solving
-20 + 10f = 22 + 7f

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-7f' to each side of the equation.
-20 + 10f + -7f = 22 + 7f + -7f

Combine like terms: 10f + -7f = 3f
-20 + 3f = 22 + 7f + -7f

Combine like terms: 7f + -7f = 0
-20 + 3f = 22 + 0
-20 + 3f = 22

Add '20' to each side of the equation.
-20 + 20 + 3f = 22 + 20

Combine like terms: -20 + 20 = 0
0 + 3f = 22 + 20
3f = 22 + 20

Combine like terms: 22 + 20 = 42
3f = 42

Divide each side by '3'.
f = 14

Simplifying
f = 14

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