5(2f+3)=2(2f-1)

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Solution for 5(2f+3)=2(2f-1) equation: 



5(2f+3)=2(2f-1)

We move all terms to the left:

5(2f+3)-(2(2f-1))=0

We multiply parentheses

10f-(2(2f-1))+15=0



We calculate terms in parentheses: -(2(2f-1)), so:

2(2f-1)

We multiply parentheses

4f-2

Back to the equation:

-(4f-2)



We get rid of parentheses

10f-4f+2+15=0

We add all the numbers together, and all the variables

6f+17=0

We move all terms containing f to the left, all other terms to the right

6f=-17

f=-17/6

f=-2+5/6

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