5(2c-4)=3(4c+4)

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Solution for 5(2c-4)=3(4c+4) equation:


Simplifying
5(2c + -4) = 3(4c + 4)

Reorder the terms:
5(-4 + 2c) = 3(4c + 4)
(-4 * 5 + 2c * 5) = 3(4c + 4)
(-20 + 10c) = 3(4c + 4)

Reorder the terms:
-20 + 10c = 3(4 + 4c)
-20 + 10c = (4 * 3 + 4c * 3)
-20 + 10c = (12 + 12c)

Solving
-20 + 10c = 12 + 12c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-12c' to each side of the equation.
-20 + 10c + -12c = 12 + 12c + -12c

Combine like terms: 10c + -12c = -2c
-20 + -2c = 12 + 12c + -12c

Combine like terms: 12c + -12c = 0
-20 + -2c = 12 + 0
-20 + -2c = 12

Add '20' to each side of the equation.
-20 + 20 + -2c = 12 + 20

Combine like terms: -20 + 20 = 0
0 + -2c = 12 + 20
-2c = 12 + 20

Combine like terms: 12 + 20 = 32
-2c = 32

Divide each side by '-2'.
c = -16

Simplifying
c = -16

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