5(2c-1)=43+4c

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Solution for 5(2c-1)=43+4c equation: 



5(2c-1)=43+4c

We move all terms to the left:

5(2c-1)-(43+4c)=0

We add all the numbers together, and all the variables

5(2c-1)-(4c+43)=0

We multiply parentheses

10c-(4c+43)-5=0

We get rid of parentheses

10c-4c-43-5=0

We add all the numbers together, and all the variables

6c-48=0

We move all terms containing c to the left, all other terms to the right

6c=48

c=48/6

c=8

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