5(2c-)=2(c+11)

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Solution for 5(2c-)=2(c+11) equation: 



5(2c-)=2(c+11)

We move all terms to the left:

5(2c-)-(2(c+11))=0

We add all the numbers together, and all the variables

5(+2c)-(2(c+11))=0

We multiply parentheses

10c-(2(c+11))=0



We calculate terms in parentheses: -(2(c+11)), so:

2(c+11)

We multiply parentheses

2c+22

Back to the equation:

-(2c+22)



We get rid of parentheses

10c-2c-22=0

We add all the numbers together, and all the variables

8c-22=0

We move all terms containing c to the left, all other terms to the right

8c=22

c=22/8

c=2+3/4

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