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5(2c+7)-3c=(c+5)
We move all terms to the left:
5(2c+7)-3c-((c+5))=0
We add all the numbers together, and all the variables
-3c+5(2c+7)-((c+5))=0
We multiply parentheses
-3c+10c-((c+5))+35=0
We calculate terms in parentheses: -((c+5)), so:We add all the numbers together, and all the variables
(c+5)
We get rid of parentheses
c+5
Back to the equation:
-(c+5)
7c-(c+5)+35=0
We get rid of parentheses
7c-c-5+35=0
We add all the numbers together, and all the variables
6c+30=0
We move all terms containing c to the left, all other terms to the right
6c=-30
c=-30/6
c=-5
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