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5(2c+7)-3c=(7c+5)
We move all terms to the left:
5(2c+7)-3c-((7c+5))=0
We add all the numbers together, and all the variables
-3c+5(2c+7)-((7c+5))=0
We multiply parentheses
-3c+10c-((7c+5))+35=0
We calculate terms in parentheses: -((7c+5)), so:We add all the numbers together, and all the variables
(7c+5)
We get rid of parentheses
7c+5
Back to the equation:
-(7c+5)
7c-(7c+5)+35=0
We get rid of parentheses
7c-7c-5+35=0
We add all the numbers together, and all the variables
30!=0
There is no solution for this equation
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