5(2c+3)-8=3(4c+2)-2c

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Solution for 5(2c+3)-8=3(4c+2)-2c equation:


Simplifying
5(2c + 3) + -8 = 3(4c + 2) + -2c

Reorder the terms:
5(3 + 2c) + -8 = 3(4c + 2) + -2c
(3 * 5 + 2c * 5) + -8 = 3(4c + 2) + -2c
(15 + 10c) + -8 = 3(4c + 2) + -2c

Reorder the terms:
15 + -8 + 10c = 3(4c + 2) + -2c

Combine like terms: 15 + -8 = 7
7 + 10c = 3(4c + 2) + -2c

Reorder the terms:
7 + 10c = 3(2 + 4c) + -2c
7 + 10c = (2 * 3 + 4c * 3) + -2c
7 + 10c = (6 + 12c) + -2c

Combine like terms: 12c + -2c = 10c
7 + 10c = 6 + 10c

Add '-10c' to each side of the equation.
7 + 10c + -10c = 6 + 10c + -10c

Combine like terms: 10c + -10c = 0
7 + 0 = 6 + 10c + -10c
7 = 6 + 10c + -10c

Combine like terms: 10c + -10c = 0
7 = 6 + 0
7 = 6

Solving
7 = 6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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