5(2c+1)=3(c+8)+2c

Solution for 5(2c+1)=3(c+8)+2c equation:

5(2c+1)=3(c+8)+2c

We move all terms to the left:

5(2c+1)-(3(c+8)+2c)=0

We multiply parentheses

10c-(3(c+8)+2c)+5=0


We calculate terms in parentheses: -(3(c+8)+2c), so:

3(c+8)+2c

We add all the numbers together, and all the variables

2c+3(c+8)

We multiply parentheses

2c+3c+24

We add all the numbers together, and all the variables

5c+24

Back to the equation:

-(5c+24)


We get rid of parentheses

10c-5c-24+5=0

We add all the numbers together, and all the variables

5c-19=0

We move all terms containing c to the left, all other terms to the right

5c=19

c=19/5

c=3+4/5