5(2c+1)-6(c+3)=-43

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Solution for 5(2c+1)-6(c+3)=-43 equation: 



5(2c+1)-6(c+3)=-43

We move all terms to the left:

5(2c+1)-6(c+3)-(-43)=0

We add all the numbers together, and all the variables

5(2c+1)-6(c+3)+43=0

We multiply parentheses

10c-6c+5-18+43=0

We add all the numbers together, and all the variables

4c+30=0

We move all terms containing c to the left, all other terms to the right

4c=-30

c=-30/4

c=-7+1/2

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