5(2b-8)=-3(3+b)+8

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Solution for 5(2b-8)=-3(3+b)+8 equation: 



5(2b-8)=-3(3+b)+8

We move all terms to the left:

5(2b-8)-(-3(3+b)+8)=0

We add all the numbers together, and all the variables

5(2b-8)-(-3(b+3)+8)=0

We multiply parentheses

10b-(-3(b+3)+8)-40=0



We calculate terms in parentheses: -(-3(b+3)+8), so:

-3(b+3)+8

We multiply parentheses

-3b-9+8

We add all the numbers together, and all the variables

-3b-1

Back to the equation:

-(-3b-1)



We get rid of parentheses

10b+3b+1-40=0

We add all the numbers together, and all the variables

13b-39=0

We move all terms containing b to the left, all other terms to the right

13b=39

b=39/13

b=3

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