5(2b-4)6b=-7+60

Solution for 5(2b-4)6b=-7+60 equation:

5(2b-4)6b=-7+60

We move all terms to the left:

5(2b-4)6b-(-7+60)=0

We add all the numbers together, and all the variables

5(2b-4)6b-53=0

We multiply parentheses

60b^2-120b-53=0

a = 60; b = -120; c = -53;
Δ = b2-4ac
Δ = -1202-4·60·(-53)
Δ = 27120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{27120}=\sqrt{16*1695}=\sqrt{16}*\sqrt{1695}=4\sqrt{1695}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-4\sqrt{1695}}{2*60}=\frac{120-4\sqrt{1695}}{120}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+4\sqrt{1695}}{2*60}=\frac{120+4\sqrt{1695}}{120}
$